12y-9y^2=0

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Solution for 12y-9y^2=0 equation:



12y-9y^2=0
a = -9; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-9)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-9}=\frac{-24}{-18} =1+1/3 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-9}=\frac{0}{-18} =0 $

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